mysql sum求和的方法:1、通过“select sum(value) as value from table where user_id”方式实现单一求和;2、通过嵌套语句多条件求和,语法如“(select sum(value) from table where type = 6 and type_son = 1) as xj0”。

本教程操作环境:Windows10系统、MySQL5.7版本、Dell G3电脑。

mysql sum求和使用方法是什么?

MySQL SUM() 带条件的求和方法与多条件的求和方法

一、单一的求和。

select sum(value) as value from table where user_id = 1 and type = 6 and type_son = 2
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value 为求和的字段。

as 后面是 sum 求和后给它一个名称。

二、SQL语句中嵌套语句多条件求和。

select 
 
(select sum(value) from table where type = 6 and type_son = 1) as xj0,
 
(select sum(value) from table where type = 6 and type_son = 2) as xj1,
 
(select sum(value) from table where type = 3 and type_son = 3) as xj2,
 
(select sum(value) from table where type = 4 and type_son = 3) as xj3
 
from table where user_id = 1 limit 0,1
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as 后面是 sum 求和后给它一个名称,这样就不会冲突。

三、与第二个一样,但是不采取语句嵌套的方式求和,而是使用 sum 判断求和。

select 
 
sum(IF(type = 6 and type_son = 1,value,NULL)) as xj0,
 
sum(IF(type = 6 and type_son = 2,value,NULL)) as xj1,
 
sum(IF(type = 3 and type_son = 0,value,NULL)) as xj2,
 
sum(IF(type = 4 and type_son = 3,value,NULL)) as xj3
 
from table where user_id = 1
 
 
sum(IF('条件判断','求和的字段','NULL不计算'))  as  '别名'
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我觉得第三个的方式比前面两个的方式要好。

YII 2.0 使用 SUM 求和

$v['alls_bonus'] = AccountingLog::find()
        ->select(["
            sum( IF(type = 6 and type_son = 1,value,NULL) ) as xj0,
            sum( IF(type = 6 and type_son = 4,value,NULL) ) as xj1,
            sum( IF(type = 8 and type_son = 4,value,NULL) ) as xj2, 
            sum( IF(type = 3 and type_son = 1,value,NULL) ) as xj3
        "])
        ->where(['user_id'=>1])
        ->asArray()
        ->one();
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注意要在 select 里面加 ["sum........"],否则会报错

以上就是mysql sum求和使用方法是什么的详细内容,转载自php中文网

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